v^2+7v+8=0

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Solution for v^2+7v+8=0 equation: 



v^2+7v+8=0

a = 1; b = 7; c = +8;
Δ = b2-4ac
Δ = 72-4·1·8
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{17}}{2*1}=\frac{-7-\sqrt{17}}{2}
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{17}}{2*1}=\frac{-7+\sqrt{17}}{2}
$

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